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Question

s - character of $$sp,\ sp^2$$ and $$sp^3$$ - hybrid orbitals follows the decreasing order.

A
$$sp > sp^2 > sp^3$$
B
$$sp^3 > sp^2 > sp$$
C
$$sp^2 > sp^3 > sp$$
D
$$sp^2 > sp > sp^3$$
Solution
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Correct option is B. $$sp > sp^2 > sp^3$$

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